Seems like an interesting effort. A developer is building an alternative Java-based backend to Lemmy’s Rust-based one, with the goal of building in a handful of different features. The dev is looking at using this compatibility to migrate their instance over to the new platform, while allowing the community to use their apps of choice.
Predictable in what sense?
If you say the function should only recieve one argument and returns always boolean. It is predictable to only allow the wanted args and forces you to return a boolean.
For example in a less predictable programming language e.g. Python: I can do all above but python does not stop anyone to put more or less arguments to a function, or a developer not adding typehints or not complying to them and return a string instead of a boolean.
But i had it wrong rust is similar to java on that part.
But still it is a lot more popular and easier to start with. So there will be a lot more contributor to sublinks than lemmy ever had.
Well in that sense Rust is even more predictable than Java. In Java you can always get back exception that bubbled up the stack. Rust function would in that case return Result that you need to handle somehow before getting the value.
That i dont understand? How can it be a result that i need to handle? If its not correct than java will throw an error. ( As expected, shit in shit out )
It’s a great and probably the best error system I’ve seen, instead of just throwing errors and having bulky try catch statements and such there’s just a result type.
Say you have a function that returns a boolean in which something could error, the function would return a Result<bool, Error> and that’s it. Calling the function you can choose to do anything you want with that possible Error, including ignoring it or logging or anything you could want.
It’s extremely simple.
If I except a boolean, there is an error and get a Result, is Result an object? How do I know if I get a bool or error?
You always get a Result. On that result you can call
result.unwrap()(give me the bool or crash) orresult.unwrap_or_default()(give me bool orfalseif there was error) or any other way you can think of. The point is that Rust won’t let you get value out of that Result until you somehow didn’t handle possible failure. If function does not return Result and returns just value directly, you (as a function caller) are guaranteed to always get a value, you can rely on there not being a failure that the function didn’t handle internally.The difference being where you handle the error?
It sounds to me like Java works in kinda the same way. You either use
throws Exceptionand require the caller to handle the exception when it occurs, or you handle it yourself and return whatever makes sense when that happens (or whatever you want to do before you do a return). The main difference being how the error is delivered.Java has class similar to Result called Optional.
Yeah I suppose ignoring unchecked exceptions, it’s pretty similar situation, although the guarantees are a bit stronger in Rust IMO as the fallibility is always in the function signature.
Ergonomically I personally like Result more than exceptions. You can work with it like with any other enum including things like
result.ok()which gives you Option. (similar to javaOptionalI think) There is some syntactic sugar like the?operator, that will just let you bubble the error up the stack (assuming the return type of the function is also Result) - ie:maybe_do_something()?. But it really is just Enum, so you can do Enum-y things with it:// similar to try-catch, but you can do this with any Enum if let Ok(value) = maybe_do_something() { println!("Value is {}", value) } // Call closure on Ok variant, return 0 if any of the two function fails let some_number = maybe_number() .and_then(|number| process_number_perhaps(number)) // this can also fail .unwrap_or(0);In that sense it’s very similar to java’s Optional if it could also carry the Exception value and if it was mandatory for any fallible function.
Also (this is besides the point) Result in Rust is just compile-time “zero cost” abstraction. It does not actually compile to any code in the binary. I’m not familiar with Java, but I think at least the unchecked exceptions introduce runtime cost?
Here’s some examples written on my phone:
match result { Ok(bool_name) => whatever, Err(error_type) => whatever, } if let Ok(bool_name) = result { whatever } if result.is_ok() { whatever } let whatever = result.unwrap_or_default(); let whatever = result?;And there’s many other awesome ways to use a Result including turning it into an Option or unwrapping it unsafely. I recommend you just search “Rust book” on your search engine and browse it. Here’s the docs to the Result enum.
Ah, so it is like a wrapper enum,
okcontains the data type you want anderrthe error object?Exactly! The other wrapper enum I named (Option) is the same kind of concept but with
Some(value)andNone.