• emptiestplace@lemmy.ml
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    7 months ago

    From the technical sense it doesn’t have to have 4 drives

    Please explain how you think you can distribute two sets of parity data across a three drive array?

    • meteokr@community.adiquaints.moe
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      7 months ago

      Drive 1: A, Drive 2: 1/2 A, Drive 3: 2/2 A. Drive 2 + Drive 3 = Drive 1. Hmm that would only be one set of the party though. So you could also add 1/2 of A to Drive 1, and 2/2 to Drive 2 so that the parity on Drive 1 + Drive 2 = Drive 3. Which is extremely silly, and doesn’t make a lot of sense to use in the real world.