I know it’s possible to subscribe to a Mastodon user on a Lemmy instance, but it seems to me like this is of limited utility since the more standard use case on Mastodon is following tags rather than users. So, is it possible to somehow follow a Mastodon tag using Lemmy and get posts with that tag integrated into your Lemmy feed?

Edit: Never post before fully woken up. It is not possible to subscribe to another user directly on Lemmy, whether they’re on Lemmy or Mastodon. That’s how things work on Mastodon, not on Lemmy. It is possible to find Mastodon users by using the instance search feature, though, as I’ve described in a reply to @Malgas@beehaw.org below, but you so far can’t really use this to achieve anything very useful, as far as I can tell.

Edit 2: It seems like something like this theoretically could be set up, but it’s way more complicated than what I initially asked for. You would need:

  • A dedicated Lemmy instance for Mastodon tag-based crossposting (probably)
  • Some kind of form on a site where users who want to follow a Mastodon tag that is not already set up as a Lemmy community could submit the tag they want added, which would automatically set up:
  • A Lemmy community for that tag on the aforementioned instance, and
  • A Mastodon hastag bot that automatically crossposts all Mastodon posts with that tag to that community

Whether something like this already exists, I have no idea, but I get the feeling it could actually be useful.

  • AnbalsilferOP
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    1 year ago

    Thanks for that input, that’s very cool that those relays exist. I have to apologize anyway though because I apparently was pretty confused when I made the original post, because on Lemmy you can’t directly follow other Lemmy users at all, whether they’re on Mastodon or Lemmy.

    Something like what I envisioned might still be workable, but it would take a bit more effort and savvy. It would probably require a Mastodon hashtag bot as well as a dedicated Lemmy community for each tag for the bot to post into. See my edited OP.